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very end of the function). If there is a nonzero value at that offset, the code loads that value into ESI and jumps back to ntdll.7C92148B, which is the callback calling code you just examined. It looks like you re looking at a loop that constantly calls into the callback and traverses some kind of linked list that starts at offset +0 of the root data structure. Each item seems to be at least 0x1c bytes long, because offset +18 of that structure is passed as the last parameter in the callback. Let s see what happens when the callback returns a nonzero value.

uncorrelated variables. The remainder of the calculation proceeds as in the uncorrelated case, using the new variables. When the iterations have converged, the x variables are back-calculated.

7C92149E 7C9214A1 7C9214A3 7C9214A6 7C9214A8 7C9214AE 7C9214B0 7C9214B1 7C9214B4 7C9214B6 7C9214B7 7C9214B8 CMP EAX,1 JNZ SHORT ntdll.7C9214BB MOV EAX,DWORD PTR [ESI+8] TEST EAX,EAX JNZ ntdll.7C924F22 PUSH 3 POP EAX MOV ECX,DWORD PTR [EBP+C] MOV DWORD PTR [ECX],ESI POP ESI POP EBP RET 8

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Low and Tang (1997a) proposed a very ef cient procedure that takes advantage of the optimization and solution techniques that are available in modern spreadsheets and mathematical software packages. They work directly with the correlated variables themselves without any rotations or transformations. If x is the vector of uncertain variables and C is their covariance matrix (not the correlation matrix) and is the vector of their means, they show that the Hasofer Lind reliability index is = min (x )T C 1 (x ) (16.56)

First of all, it seems that the callback returns some kind of a number and not a pointer. This could be a Boolean, but you don t know for sure yet. The first check tests for ReturnValue != 1 and loads offset +8 into EAX if that condition is not satisfied. Offset +8 in ESI is then tested for a nonzero value, and if it is zero the code sets EAX to 3 (using the PUSH-POP method described earlier), and proceeds to what is clearly this function s epilogue. At this point, it becomes clear that the reason for loading the value 3 into EAX was to return the value 3 to the caller. Notice how the second parameter is treated as a pointer, and that this pointer receives the current value of ESI, which is that unknown structure we discussed. This is important because it seems that this function is traversing a different list than the one you ve encountered so far. Apparently, there is some kind of a linked list that starts at offset +0 in the root table data structure. So far you ve seen what happens when the callback returns 0 or when it returns 1. When the callback returns some other value, the conditional jump you looked at earlier is taken and execution continues at ntdll.7C9214BB. Here is the code at that address:

Often it is more what you do about handling the lows, rather than how you handle the highs that affects performance How do you refocus as quickly as possible If you are campaigning on your own this can be especially dif cult without other people to help you A close friend, girl/boyfriend, husband/wife may be the ideal person to help elevate your mood, or you may nd it better to work it through on your own Experience is important here, and sometimes you may nd out what not to do (to improve your mood) rst There are so many variables in sailing, most of which are completely beyond your control Often you may feel the weather (wind, waves, current, etc) is conspiring against you However, over time, the law of averages says things will go your way: you just have to stick with it.

This snippet sets EAX to 1 and jumps back into ntdll.7C9214B1, that you ve just examined. Recall that that sequence doesn t affect EAX, so it is effectively returning 1 to the caller.

subject to the constraint that x must satisfy the failure criterion that M = 0. The procedure is as follows: 1. Values of the means and covariance matrix are de ned and C 1 is calculated. 2. The functional form of the following equation is entered 2 = (x )T C 1 (x ) (16.57)

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